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6m^2-37m+6=0
a = 6; b = -37; c = +6;
Δ = b2-4ac
Δ = -372-4·6·6
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-35}{2*6}=\frac{2}{12} =1/6 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+35}{2*6}=\frac{72}{12} =6 $
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